3.16.44 \(\int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx\) [1544]

3.16.44.1 Optimal result
3.16.44.2 Mathematica [A] (verified)
3.16.44.3 Rubi [A] (verified)
3.16.44.4 Maple [A] (verified)
3.16.44.5 Fricas [A] (verification not implemented)
3.16.44.6 Sympy [F(-1)]
3.16.44.7 Maxima [A] (verification not implemented)
3.16.44.8 Giac [A] (verification not implemented)
3.16.44.9 Mupad [B] (verification not implemented)

3.16.44.1 Optimal result

Integrand size = 31, antiderivative size = 315 \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=-\frac {\left (a^2-b^2\right )^3 (A b-a B) \log (a+b \sin (c+d x))}{b^8 d}+\frac {\left (a^5 A b-3 a^3 A b^3+3 a A b^5-a^6 B+3 a^4 b^2 B-3 a^2 b^4 B+b^6 B\right ) \sin (c+d x)}{b^7 d}-\frac {\left (a^4-3 a^2 b^2+3 b^4\right ) (A b-a B) \sin ^2(c+d x)}{2 b^6 d}+\frac {\left (a^3 A b-3 a A b^3-a^4 B+3 a^2 b^2 B-3 b^4 B\right ) \sin ^3(c+d x)}{3 b^5 d}-\frac {\left (a^2-3 b^2\right ) (A b-a B) \sin ^4(c+d x)}{4 b^4 d}+\frac {\left (a A b-a^2 B+3 b^2 B\right ) \sin ^5(c+d x)}{5 b^3 d}-\frac {(A b-a B) \sin ^6(c+d x)}{6 b^2 d}-\frac {B \sin ^7(c+d x)}{7 b d} \]

output
-(a^2-b^2)^3*(A*b-B*a)*ln(a+b*sin(d*x+c))/b^8/d+(A*a^5*b-3*A*a^3*b^3+3*A*a 
*b^5-B*a^6+3*B*a^4*b^2-3*B*a^2*b^4+B*b^6)*sin(d*x+c)/b^7/d-1/2*(a^4-3*a^2* 
b^2+3*b^4)*(A*b-B*a)*sin(d*x+c)^2/b^6/d+1/3*(A*a^3*b-3*A*a*b^3-B*a^4+3*B*a 
^2*b^2-3*B*b^4)*sin(d*x+c)^3/b^5/d-1/4*(a^2-3*b^2)*(A*b-B*a)*sin(d*x+c)^4/ 
b^4/d+1/5*(A*a*b-B*a^2+3*B*b^2)*sin(d*x+c)^5/b^3/d-1/6*(A*b-B*a)*sin(d*x+c 
)^6/b^2/d-1/7*B*sin(d*x+c)^7/b/d
 
3.16.44.2 Mathematica [A] (verified)

Time = 0.62 (sec) , antiderivative size = 218, normalized size of antiderivative = 0.69 \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=\frac {\frac {(A b-a B) \left (15 b^4 \left (-a^2+b^2\right ) \cos ^4(c+d x)+10 b^6 \cos ^6(c+d x)-60 \left (a^2-b^2\right )^3 \log (a+b \sin (c+d x))+60 a b \left (a^4-3 a^2 b^2+3 b^4\right ) \sin (c+d x)-30 b^2 \left (a^2-b^2\right )^2 \sin ^2(c+d x)+20 a b^3 \left (a^2-3 b^2\right ) \sin ^3(c+d x)+12 a b^5 \sin ^5(c+d x)\right )}{60 b}+\frac {b^6 B (1225 \sin (c+d x)+245 \sin (3 (c+d x))+49 \sin (5 (c+d x))+5 \sin (7 (c+d x)))}{2240}}{b^7 d} \]

input
Integrate[(Cos[c + d*x]^7*(A + B*Sin[c + d*x]))/(a + b*Sin[c + d*x]),x]
 
output
(((A*b - a*B)*(15*b^4*(-a^2 + b^2)*Cos[c + d*x]^4 + 10*b^6*Cos[c + d*x]^6 
- 60*(a^2 - b^2)^3*Log[a + b*Sin[c + d*x]] + 60*a*b*(a^4 - 3*a^2*b^2 + 3*b 
^4)*Sin[c + d*x] - 30*b^2*(a^2 - b^2)^2*Sin[c + d*x]^2 + 20*a*b^3*(a^2 - 3 
*b^2)*Sin[c + d*x]^3 + 12*a*b^5*Sin[c + d*x]^5))/(60*b) + (b^6*B*(1225*Sin 
[c + d*x] + 245*Sin[3*(c + d*x)] + 49*Sin[5*(c + d*x)] + 5*Sin[7*(c + d*x) 
]))/2240)/(b^7*d)
 
3.16.44.3 Rubi [A] (verified)

Time = 0.61 (sec) , antiderivative size = 293, normalized size of antiderivative = 0.93, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {3042, 3316, 27, 652, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\cos (c+d x)^7 (A+B \sin (c+d x))}{a+b \sin (c+d x)}dx\)

\(\Big \downarrow \) 3316

\(\displaystyle \frac {\int \frac {(A b+B \sin (c+d x) b) \left (b^2-b^2 \sin ^2(c+d x)\right )^3}{b (a+b \sin (c+d x))}d(b \sin (c+d x))}{b^7 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {(A b+B \sin (c+d x) b) \left (b^2-b^2 \sin ^2(c+d x)\right )^3}{a+b \sin (c+d x)}d(b \sin (c+d x))}{b^8 d}\)

\(\Big \downarrow \) 652

\(\displaystyle \frac {\int \left (-b^6 B \sin ^6(c+d x)-b^5 (A b-a B) \sin ^5(c+d x)-b^4 \left (B a^2-A b a-3 b^2 B\right ) \sin ^4(c+d x)+b^3 \left (a^2-3 b^2\right ) (a B-A b) \sin ^3(c+d x)-b^2 \left (B a^4-A b a^3-3 b^2 B a^2+3 A b^3 a+3 b^4 B\right ) \sin ^2(c+d x)+b \left (a^4-3 b^2 a^2+3 b^4\right ) (a B-A b) \sin (c+d x)+a^5 A b \left (1-\frac {\left (a^2-b^2\right ) \left (B a^4-2 b^2 B a^2+3 A b^3 a+b^4 B\right )}{a^5 A b}\right )+\frac {\left (a^2-b^2\right )^3 (a B-A b)}{a+b \sin (c+d x)}\right )d(b \sin (c+d x))}{b^8 d}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {-\left (a^2-b^2\right )^3 (A b-a B) \log (a+b \sin (c+d x))+\frac {1}{5} b^5 \left (a^2 (-B)+a A b+3 b^2 B\right ) \sin ^5(c+d x)-\frac {1}{4} b^4 \left (a^2-3 b^2\right ) (A b-a B) \sin ^4(c+d x)-\frac {1}{2} b^2 \left (a^4-3 a^2 b^2+3 b^4\right ) (A b-a B) \sin ^2(c+d x)+\frac {1}{3} b^3 \left (a^4 (-B)+a^3 A b+3 a^2 b^2 B-3 a A b^3-3 b^4 B\right ) \sin ^3(c+d x)+b \left (a^6 (-B)+a^5 A b+3 a^4 b^2 B-3 a^3 A b^3-3 a^2 b^4 B+3 a A b^5+b^6 B\right ) \sin (c+d x)-\frac {1}{6} b^6 (A b-a B) \sin ^6(c+d x)-\frac {1}{7} b^7 B \sin ^7(c+d x)}{b^8 d}\)

input
Int[(Cos[c + d*x]^7*(A + B*Sin[c + d*x]))/(a + b*Sin[c + d*x]),x]
 
output
(-((a^2 - b^2)^3*(A*b - a*B)*Log[a + b*Sin[c + d*x]]) + b*(a^5*A*b - 3*a^3 
*A*b^3 + 3*a*A*b^5 - a^6*B + 3*a^4*b^2*B - 3*a^2*b^4*B + b^6*B)*Sin[c + d* 
x] - (b^2*(a^4 - 3*a^2*b^2 + 3*b^4)*(A*b - a*B)*Sin[c + d*x]^2)/2 + (b^3*( 
a^3*A*b - 3*a*A*b^3 - a^4*B + 3*a^2*b^2*B - 3*b^4*B)*Sin[c + d*x]^3)/3 - ( 
b^4*(a^2 - 3*b^2)*(A*b - a*B)*Sin[c + d*x]^4)/4 + (b^5*(a*A*b - a^2*B + 3* 
b^2*B)*Sin[c + d*x]^5)/5 - (b^6*(A*b - a*B)*Sin[c + d*x]^6)/6 - (b^7*B*Sin 
[c + d*x]^7)/7)/(b^8*d)
 

3.16.44.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 652
Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.)*((a_) + (c_.)*(x_ 
)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*(f + g*x)^n*(a + c 
*x^2)^p, x], x] /; FreeQ[{a, c, d, e, f, g, m, n}, x] && IGtQ[p, 0]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3316
Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_ 
.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp[1/(b^p* 
f)   Subst[Int[(a + x)^m*(c + (d/b)*x)^n*(b^2 - x^2)^((p - 1)/2), x], x, b* 
Sin[e + f*x]], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IntegerQ[(p - 1) 
/2] && NeQ[a^2 - b^2, 0]
 
3.16.44.4 Maple [A] (verified)

Time = 1.18 (sec) , antiderivative size = 374, normalized size of antiderivative = 1.19

method result size
parallelrisch \(\frac {-6720 \left (a -b \right )^{3} \left (a +b \right )^{3} \left (A b -B a \right ) \ln \left (2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )+6720 \left (a -b \right )^{3} \left (a +b \right )^{3} \left (A b -B a \right ) \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+35 b \left (48 b \left (a^{4}-\frac {5}{2} a^{2} b^{2}+\frac {29}{16} b^{4}\right ) \left (A b -B a \right ) \cos \left (2 d x +2 c \right )+\left (-16 A \,a^{3} b^{3}+36 A a \,b^{5}+16 B \,a^{4} b^{2}-36 B \,a^{2} b^{4}+21 B \,b^{6}\right ) \sin \left (3 d x +3 c \right )-6 b^{3} \left (a^{2}-2 b^{2}\right ) \left (A b -B a \right ) \cos \left (4 d x +4 c \right )+\frac {12 b^{4} \left (A a b -B \,a^{2}+\frac {7}{4} B \,b^{2}\right ) \sin \left (5 d x +5 c \right )}{5}+\left (A \,b^{6}-B a \,b^{5}\right ) \cos \left (6 d x +6 c \right )+\frac {3 B \,b^{6} \sin \left (7 d x +7 c \right )}{7}+\left (192 A \,a^{5} b -528 A \,a^{3} b^{3}+456 A a \,b^{5}-192 B \,a^{6}+528 B \,a^{4} b^{2}-456 B \,a^{2} b^{4}+105 B \,b^{6}\right ) \sin \left (d x +c \right )-48 \left (a^{4}-\frac {21}{8} a^{2} b^{2}+\frac {25}{12} b^{4}\right ) b \left (A b -B a \right )\right )}{6720 d \,b^{8}}\) \(374\)
derivativedivides \(-\frac {-\frac {3 B \,a^{4} b^{2} \sin \left (d x +c \right )-3 B \,a^{2} b^{4} \sin \left (d x +c \right )+A \,a^{5} b \sin \left (d x +c \right )-3 A \,a^{3} b^{3} \sin \left (d x +c \right )+3 A a \,b^{5} \sin \left (d x +c \right )-B \,a^{6} \sin \left (d x +c \right )+B \,b^{6} \sin \left (d x +c \right )+B \,a^{2} b^{4} \left (\sin ^{3}\left (d x +c \right )\right )+\frac {3 B a \,b^{5} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+\frac {3 A \,a^{2} b^{4} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+\frac {B \,a^{5} b \left (\sin ^{2}\left (d x +c \right )\right )}{2}-\frac {3 B \,a^{3} b^{3} \left (\sin ^{2}\left (d x +c \right )\right )}{2}-\frac {A \,a^{4} b^{2} \left (\sin ^{2}\left (d x +c \right )\right )}{2}-\frac {3 B a \,b^{5} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {A \,a^{3} b^{3} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-A a \,b^{5} \left (\sin ^{3}\left (d x +c \right )\right )-\frac {B \,a^{4} b^{2} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {A \,a^{2} b^{4} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {B \,a^{3} b^{3} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {B a \,b^{5} \left (\sin ^{6}\left (d x +c \right )\right )}{6}+\frac {A a \,b^{5} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {B \,a^{2} b^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {B \left (\sin ^{7}\left (d x +c \right )\right ) b^{6}}{7}-\frac {A \,b^{6} \left (\sin ^{6}\left (d x +c \right )\right )}{6}-B \,b^{6} \left (\sin ^{3}\left (d x +c \right )\right )+\frac {3 B \,b^{6} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {3 A \,b^{6} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+\frac {3 A \,b^{6} \left (\sin ^{4}\left (d x +c \right )\right )}{4}}{b^{7}}+\frac {\left (A \,a^{6} b -3 A \,a^{4} b^{3}+3 A \,a^{2} b^{5}-A \,b^{7}-B \,a^{7}+3 B \,a^{5} b^{2}-3 B \,a^{3} b^{4}+B a \,b^{6}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{b^{8}}}{d}\) \(508\)
default \(-\frac {-\frac {3 B \,a^{4} b^{2} \sin \left (d x +c \right )-3 B \,a^{2} b^{4} \sin \left (d x +c \right )+A \,a^{5} b \sin \left (d x +c \right )-3 A \,a^{3} b^{3} \sin \left (d x +c \right )+3 A a \,b^{5} \sin \left (d x +c \right )-B \,a^{6} \sin \left (d x +c \right )+B \,b^{6} \sin \left (d x +c \right )+B \,a^{2} b^{4} \left (\sin ^{3}\left (d x +c \right )\right )+\frac {3 B a \,b^{5} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+\frac {3 A \,a^{2} b^{4} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+\frac {B \,a^{5} b \left (\sin ^{2}\left (d x +c \right )\right )}{2}-\frac {3 B \,a^{3} b^{3} \left (\sin ^{2}\left (d x +c \right )\right )}{2}-\frac {A \,a^{4} b^{2} \left (\sin ^{2}\left (d x +c \right )\right )}{2}-\frac {3 B a \,b^{5} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {A \,a^{3} b^{3} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-A a \,b^{5} \left (\sin ^{3}\left (d x +c \right )\right )-\frac {B \,a^{4} b^{2} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {A \,a^{2} b^{4} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {B \,a^{3} b^{3} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {B a \,b^{5} \left (\sin ^{6}\left (d x +c \right )\right )}{6}+\frac {A a \,b^{5} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {B \,a^{2} b^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {B \left (\sin ^{7}\left (d x +c \right )\right ) b^{6}}{7}-\frac {A \,b^{6} \left (\sin ^{6}\left (d x +c \right )\right )}{6}-B \,b^{6} \left (\sin ^{3}\left (d x +c \right )\right )+\frac {3 B \,b^{6} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {3 A \,b^{6} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+\frac {3 A \,b^{6} \left (\sin ^{4}\left (d x +c \right )\right )}{4}}{b^{7}}+\frac {\left (A \,a^{6} b -3 A \,a^{4} b^{3}+3 A \,a^{2} b^{5}-A \,b^{7}-B \,a^{7}+3 B \,a^{5} b^{2}-3 B \,a^{3} b^{4}+B a \,b^{6}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{b^{8}}}{d}\) \(508\)
norman \(\text {Expression too large to display}\) \(1222\)
risch \(\text {Expression too large to display}\) \(1337\)

input
int(cos(d*x+c)^7*(A+B*sin(d*x+c))/(a+b*sin(d*x+c)),x,method=_RETURNVERBOSE 
)
 
output
1/6720*(-6720*(a-b)^3*(a+b)^3*(A*b-B*a)*ln(2*b*tan(1/2*d*x+1/2*c)+a*sec(1/ 
2*d*x+1/2*c)^2)+6720*(a-b)^3*(a+b)^3*(A*b-B*a)*ln(sec(1/2*d*x+1/2*c)^2)+35 
*b*(48*b*(a^4-5/2*a^2*b^2+29/16*b^4)*(A*b-B*a)*cos(2*d*x+2*c)+(-16*A*a^3*b 
^3+36*A*a*b^5+16*B*a^4*b^2-36*B*a^2*b^4+21*B*b^6)*sin(3*d*x+3*c)-6*b^3*(a^ 
2-2*b^2)*(A*b-B*a)*cos(4*d*x+4*c)+12/5*b^4*(A*a*b-B*a^2+7/4*B*b^2)*sin(5*d 
*x+5*c)+(A*b^6-B*a*b^5)*cos(6*d*x+6*c)+3/7*B*b^6*sin(7*d*x+7*c)+(192*A*a^5 
*b-528*A*a^3*b^3+456*A*a*b^5-192*B*a^6+528*B*a^4*b^2-456*B*a^2*b^4+105*B*b 
^6)*sin(d*x+c)-48*(a^4-21/8*a^2*b^2+25/12*b^4)*b*(A*b-B*a)))/d/b^8
 
3.16.44.5 Fricas [A] (verification not implemented)

Time = 0.34 (sec) , antiderivative size = 366, normalized size of antiderivative = 1.16 \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=-\frac {70 \, {\left (B a b^{6} - A b^{7}\right )} \cos \left (d x + c\right )^{6} - 105 \, {\left (B a^{3} b^{4} - A a^{2} b^{5} - B a b^{6} + A b^{7}\right )} \cos \left (d x + c\right )^{4} + 210 \, {\left (B a^{5} b^{2} - A a^{4} b^{3} - 2 \, B a^{3} b^{4} + 2 \, A a^{2} b^{5} + B a b^{6} - A b^{7}\right )} \cos \left (d x + c\right )^{2} - 420 \, {\left (B a^{7} - A a^{6} b - 3 \, B a^{5} b^{2} + 3 \, A a^{4} b^{3} + 3 \, B a^{3} b^{4} - 3 \, A a^{2} b^{5} - B a b^{6} + A b^{7}\right )} \log \left (b \sin \left (d x + c\right ) + a\right ) - 4 \, {\left (15 \, B b^{7} \cos \left (d x + c\right )^{6} - 105 \, B a^{6} b + 105 \, A a^{5} b^{2} + 280 \, B a^{4} b^{3} - 280 \, A a^{3} b^{4} - 231 \, B a^{2} b^{5} + 231 \, A a b^{6} + 48 \, B b^{7} - 3 \, {\left (7 \, B a^{2} b^{5} - 7 \, A a b^{6} - 6 \, B b^{7}\right )} \cos \left (d x + c\right )^{4} + {\left (35 \, B a^{4} b^{3} - 35 \, A a^{3} b^{4} - 63 \, B a^{2} b^{5} + 63 \, A a b^{6} + 24 \, B b^{7}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{420 \, b^{8} d} \]

input
integrate(cos(d*x+c)^7*(A+B*sin(d*x+c))/(a+b*sin(d*x+c)),x, algorithm="fri 
cas")
 
output
-1/420*(70*(B*a*b^6 - A*b^7)*cos(d*x + c)^6 - 105*(B*a^3*b^4 - A*a^2*b^5 - 
 B*a*b^6 + A*b^7)*cos(d*x + c)^4 + 210*(B*a^5*b^2 - A*a^4*b^3 - 2*B*a^3*b^ 
4 + 2*A*a^2*b^5 + B*a*b^6 - A*b^7)*cos(d*x + c)^2 - 420*(B*a^7 - A*a^6*b - 
 3*B*a^5*b^2 + 3*A*a^4*b^3 + 3*B*a^3*b^4 - 3*A*a^2*b^5 - B*a*b^6 + A*b^7)* 
log(b*sin(d*x + c) + a) - 4*(15*B*b^7*cos(d*x + c)^6 - 105*B*a^6*b + 105*A 
*a^5*b^2 + 280*B*a^4*b^3 - 280*A*a^3*b^4 - 231*B*a^2*b^5 + 231*A*a*b^6 + 4 
8*B*b^7 - 3*(7*B*a^2*b^5 - 7*A*a*b^6 - 6*B*b^7)*cos(d*x + c)^4 + (35*B*a^4 
*b^3 - 35*A*a^3*b^4 - 63*B*a^2*b^5 + 63*A*a*b^6 + 24*B*b^7)*cos(d*x + c)^2 
)*sin(d*x + c))/(b^8*d)
 
3.16.44.6 Sympy [F(-1)]

Timed out. \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=\text {Timed out} \]

input
integrate(cos(d*x+c)**7*(A+B*sin(d*x+c))/(a+b*sin(d*x+c)),x)
 
output
Timed out
 
3.16.44.7 Maxima [A] (verification not implemented)

Time = 0.21 (sec) , antiderivative size = 366, normalized size of antiderivative = 1.16 \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=-\frac {\frac {60 \, B b^{6} \sin \left (d x + c\right )^{7} - 70 \, {\left (B a b^{5} - A b^{6}\right )} \sin \left (d x + c\right )^{6} + 84 \, {\left (B a^{2} b^{4} - A a b^{5} - 3 \, B b^{6}\right )} \sin \left (d x + c\right )^{5} - 105 \, {\left (B a^{3} b^{3} - A a^{2} b^{4} - 3 \, B a b^{5} + 3 \, A b^{6}\right )} \sin \left (d x + c\right )^{4} + 140 \, {\left (B a^{4} b^{2} - A a^{3} b^{3} - 3 \, B a^{2} b^{4} + 3 \, A a b^{5} + 3 \, B b^{6}\right )} \sin \left (d x + c\right )^{3} - 210 \, {\left (B a^{5} b - A a^{4} b^{2} - 3 \, B a^{3} b^{3} + 3 \, A a^{2} b^{4} + 3 \, B a b^{5} - 3 \, A b^{6}\right )} \sin \left (d x + c\right )^{2} + 420 \, {\left (B a^{6} - A a^{5} b - 3 \, B a^{4} b^{2} + 3 \, A a^{3} b^{3} + 3 \, B a^{2} b^{4} - 3 \, A a b^{5} - B b^{6}\right )} \sin \left (d x + c\right )}{b^{7}} - \frac {420 \, {\left (B a^{7} - A a^{6} b - 3 \, B a^{5} b^{2} + 3 \, A a^{4} b^{3} + 3 \, B a^{3} b^{4} - 3 \, A a^{2} b^{5} - B a b^{6} + A b^{7}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{b^{8}}}{420 \, d} \]

input
integrate(cos(d*x+c)^7*(A+B*sin(d*x+c))/(a+b*sin(d*x+c)),x, algorithm="max 
ima")
 
output
-1/420*((60*B*b^6*sin(d*x + c)^7 - 70*(B*a*b^5 - A*b^6)*sin(d*x + c)^6 + 8 
4*(B*a^2*b^4 - A*a*b^5 - 3*B*b^6)*sin(d*x + c)^5 - 105*(B*a^3*b^3 - A*a^2* 
b^4 - 3*B*a*b^5 + 3*A*b^6)*sin(d*x + c)^4 + 140*(B*a^4*b^2 - A*a^3*b^3 - 3 
*B*a^2*b^4 + 3*A*a*b^5 + 3*B*b^6)*sin(d*x + c)^3 - 210*(B*a^5*b - A*a^4*b^ 
2 - 3*B*a^3*b^3 + 3*A*a^2*b^4 + 3*B*a*b^5 - 3*A*b^6)*sin(d*x + c)^2 + 420* 
(B*a^6 - A*a^5*b - 3*B*a^4*b^2 + 3*A*a^3*b^3 + 3*B*a^2*b^4 - 3*A*a*b^5 - B 
*b^6)*sin(d*x + c))/b^7 - 420*(B*a^7 - A*a^6*b - 3*B*a^5*b^2 + 3*A*a^4*b^3 
 + 3*B*a^3*b^4 - 3*A*a^2*b^5 - B*a*b^6 + A*b^7)*log(b*sin(d*x + c) + a)/b^ 
8)/d
 
3.16.44.8 Giac [A] (verification not implemented)

Time = 0.36 (sec) , antiderivative size = 511, normalized size of antiderivative = 1.62 \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=-\frac {\frac {60 \, B b^{6} \sin \left (d x + c\right )^{7} - 70 \, B a b^{5} \sin \left (d x + c\right )^{6} + 70 \, A b^{6} \sin \left (d x + c\right )^{6} + 84 \, B a^{2} b^{4} \sin \left (d x + c\right )^{5} - 84 \, A a b^{5} \sin \left (d x + c\right )^{5} - 252 \, B b^{6} \sin \left (d x + c\right )^{5} - 105 \, B a^{3} b^{3} \sin \left (d x + c\right )^{4} + 105 \, A a^{2} b^{4} \sin \left (d x + c\right )^{4} + 315 \, B a b^{5} \sin \left (d x + c\right )^{4} - 315 \, A b^{6} \sin \left (d x + c\right )^{4} + 140 \, B a^{4} b^{2} \sin \left (d x + c\right )^{3} - 140 \, A a^{3} b^{3} \sin \left (d x + c\right )^{3} - 420 \, B a^{2} b^{4} \sin \left (d x + c\right )^{3} + 420 \, A a b^{5} \sin \left (d x + c\right )^{3} + 420 \, B b^{6} \sin \left (d x + c\right )^{3} - 210 \, B a^{5} b \sin \left (d x + c\right )^{2} + 210 \, A a^{4} b^{2} \sin \left (d x + c\right )^{2} + 630 \, B a^{3} b^{3} \sin \left (d x + c\right )^{2} - 630 \, A a^{2} b^{4} \sin \left (d x + c\right )^{2} - 630 \, B a b^{5} \sin \left (d x + c\right )^{2} + 630 \, A b^{6} \sin \left (d x + c\right )^{2} + 420 \, B a^{6} \sin \left (d x + c\right ) - 420 \, A a^{5} b \sin \left (d x + c\right ) - 1260 \, B a^{4} b^{2} \sin \left (d x + c\right ) + 1260 \, A a^{3} b^{3} \sin \left (d x + c\right ) + 1260 \, B a^{2} b^{4} \sin \left (d x + c\right ) - 1260 \, A a b^{5} \sin \left (d x + c\right ) - 420 \, B b^{6} \sin \left (d x + c\right )}{b^{7}} - \frac {420 \, {\left (B a^{7} - A a^{6} b - 3 \, B a^{5} b^{2} + 3 \, A a^{4} b^{3} + 3 \, B a^{3} b^{4} - 3 \, A a^{2} b^{5} - B a b^{6} + A b^{7}\right )} \log \left ({\left | b \sin \left (d x + c\right ) + a \right |}\right )}{b^{8}}}{420 \, d} \]

input
integrate(cos(d*x+c)^7*(A+B*sin(d*x+c))/(a+b*sin(d*x+c)),x, algorithm="gia 
c")
 
output
-1/420*((60*B*b^6*sin(d*x + c)^7 - 70*B*a*b^5*sin(d*x + c)^6 + 70*A*b^6*si 
n(d*x + c)^6 + 84*B*a^2*b^4*sin(d*x + c)^5 - 84*A*a*b^5*sin(d*x + c)^5 - 2 
52*B*b^6*sin(d*x + c)^5 - 105*B*a^3*b^3*sin(d*x + c)^4 + 105*A*a^2*b^4*sin 
(d*x + c)^4 + 315*B*a*b^5*sin(d*x + c)^4 - 315*A*b^6*sin(d*x + c)^4 + 140* 
B*a^4*b^2*sin(d*x + c)^3 - 140*A*a^3*b^3*sin(d*x + c)^3 - 420*B*a^2*b^4*si 
n(d*x + c)^3 + 420*A*a*b^5*sin(d*x + c)^3 + 420*B*b^6*sin(d*x + c)^3 - 210 
*B*a^5*b*sin(d*x + c)^2 + 210*A*a^4*b^2*sin(d*x + c)^2 + 630*B*a^3*b^3*sin 
(d*x + c)^2 - 630*A*a^2*b^4*sin(d*x + c)^2 - 630*B*a*b^5*sin(d*x + c)^2 + 
630*A*b^6*sin(d*x + c)^2 + 420*B*a^6*sin(d*x + c) - 420*A*a^5*b*sin(d*x + 
c) - 1260*B*a^4*b^2*sin(d*x + c) + 1260*A*a^3*b^3*sin(d*x + c) + 1260*B*a^ 
2*b^4*sin(d*x + c) - 1260*A*a*b^5*sin(d*x + c) - 420*B*b^6*sin(d*x + c))/b 
^7 - 420*(B*a^7 - A*a^6*b - 3*B*a^5*b^2 + 3*A*a^4*b^3 + 3*B*a^3*b^4 - 3*A* 
a^2*b^5 - B*a*b^6 + A*b^7)*log(abs(b*sin(d*x + c) + a))/b^8)/d
 
3.16.44.9 Mupad [B] (verification not implemented)

Time = 11.99 (sec) , antiderivative size = 435, normalized size of antiderivative = 1.38 \[ \int \frac {\cos ^7(c+d x) (A+B \sin (c+d x))}{a+b \sin (c+d x)} \, dx=\frac {{\sin \left (c+d\,x\right )}^4\,\left (\frac {3\,A}{4\,b}-\frac {a\,\left (\frac {3\,B}{b}+\frac {a\,\left (\frac {A}{b}-\frac {B\,a}{b^2}\right )}{b}\right )}{4\,b}\right )}{d}-\frac {{\sin \left (c+d\,x\right )}^3\,\left (\frac {B}{b}+\frac {a\,\left (\frac {3\,A}{b}-\frac {a\,\left (\frac {3\,B}{b}+\frac {a\,\left (\frac {A}{b}-\frac {B\,a}{b^2}\right )}{b}\right )}{b}\right )}{3\,b}\right )}{d}+\frac {\sin \left (c+d\,x\right )\,\left (\frac {B}{b}+\frac {a\,\left (\frac {3\,A}{b}-\frac {a\,\left (\frac {3\,B}{b}+\frac {a\,\left (\frac {3\,A}{b}-\frac {a\,\left (\frac {3\,B}{b}+\frac {a\,\left (\frac {A}{b}-\frac {B\,a}{b^2}\right )}{b}\right )}{b}\right )}{b}\right )}{b}\right )}{b}\right )}{d}-\frac {{\sin \left (c+d\,x\right )}^6\,\left (\frac {A}{6\,b}-\frac {B\,a}{6\,b^2}\right )}{d}-\frac {{\sin \left (c+d\,x\right )}^2\,\left (\frac {3\,A}{2\,b}-\frac {a\,\left (\frac {3\,B}{b}+\frac {a\,\left (\frac {3\,A}{b}-\frac {a\,\left (\frac {3\,B}{b}+\frac {a\,\left (\frac {A}{b}-\frac {B\,a}{b^2}\right )}{b}\right )}{b}\right )}{b}\right )}{2\,b}\right )}{d}+\frac {{\sin \left (c+d\,x\right )}^5\,\left (\frac {3\,B}{5\,b}+\frac {a\,\left (\frac {A}{b}-\frac {B\,a}{b^2}\right )}{5\,b}\right )}{d}+\frac {\ln \left (a+b\,\sin \left (c+d\,x\right )\right )\,\left (B\,a^7-A\,a^6\,b-3\,B\,a^5\,b^2+3\,A\,a^4\,b^3+3\,B\,a^3\,b^4-3\,A\,a^2\,b^5-B\,a\,b^6+A\,b^7\right )}{b^8\,d}-\frac {B\,{\sin \left (c+d\,x\right )}^7}{7\,b\,d} \]

input
int((cos(c + d*x)^7*(A + B*sin(c + d*x)))/(a + b*sin(c + d*x)),x)
 
output
(sin(c + d*x)^4*((3*A)/(4*b) - (a*((3*B)/b + (a*(A/b - (B*a)/b^2))/b))/(4* 
b)))/d - (sin(c + d*x)^3*(B/b + (a*((3*A)/b - (a*((3*B)/b + (a*(A/b - (B*a 
)/b^2))/b))/b))/(3*b)))/d + (sin(c + d*x)*(B/b + (a*((3*A)/b - (a*((3*B)/b 
 + (a*((3*A)/b - (a*((3*B)/b + (a*(A/b - (B*a)/b^2))/b))/b))/b))/b))/b))/d 
 - (sin(c + d*x)^6*(A/(6*b) - (B*a)/(6*b^2)))/d - (sin(c + d*x)^2*((3*A)/( 
2*b) - (a*((3*B)/b + (a*((3*A)/b - (a*((3*B)/b + (a*(A/b - (B*a)/b^2))/b)) 
/b))/b))/(2*b)))/d + (sin(c + d*x)^5*((3*B)/(5*b) + (a*(A/b - (B*a)/b^2))/ 
(5*b)))/d + (log(a + b*sin(c + d*x))*(A*b^7 + B*a^7 - 3*A*a^2*b^5 + 3*A*a^ 
4*b^3 + 3*B*a^3*b^4 - 3*B*a^5*b^2 - A*a^6*b - B*a*b^6))/(b^8*d) - (B*sin(c 
 + d*x)^7)/(7*b*d)